Fixed() placement

[brandmaier]

I was recently confused that those statements are not equivalent:

graph = @StenoGraph begin
       a ↔ fixed(1)*b
       end

which yields
a ↔ b * Fixed{Tuple{Int64}}((1,))

 graph = @StenoGraph begin
       fixed(1)*b ↔ a
 end

which yields
b ↔ a

I think the documentation needs to be expanded to explain how exactly the fixed() modifier is supposed to be used.